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Is the higher the ENCUT, the higher the accuracy we get?

Posted: Fri Jan 06, 2012 5:16 am
by KurtG
Normally, due to ENCUT controls the size of plane wave basis sets, the answer for this question is yes.

However, in Dr. Georg Kresse's slides for the VASP course (Session 4 and Session 11), he mentioned that the pseudopotentials are always optimized for the energy cutoff 'using a minimal basis set'. And 'the PAW potentials are optimized to work at a cutoff of 250-300 eV'. So I doubt whether a result with very high cutoff energy is meaningful.

For example, I calculated some rare earth oxides, especially the ones with extended 4d and f electrons. I find the ENCUT convergence is acceptable (<20 meV for a 20-atom cell) only when the ENCUT is very large. For instance, the total energy of SrRuO3 converges at ENCUT~850 eV! 500 eV seems to converge well, but if further increase the cutoff we will get ~200 meV total energy gained. Please see the figure here.

So, in this case, whether the result with a higher cutoff has a better accuracy? or worse?

Thank you.

Is the higher the ENCUT, the higher the accuracy we get?

Posted: Fri Jan 06, 2012 11:59 am
by alex
Hi KurtG,

some remarks:
a) we prefer to look at differences of total energies in our trade rather than absolute values
b) differencies are mostly well converged at Georg's typical cut-offs
c) by the shape of your figure you probably missed the so-called 'kinetic energy error' written in the OUTCAR and added to the total energy (to account for a non-complete basis set)

Cheers,

alex

Is the higher the ENCUT, the higher the accuracy we get?

Posted: Fri Jan 06, 2012 4:02 pm
by KurtG
(a & b)yes, you are right. Most of the time only the differencies make sense.

(c) Even take into account the kinetic energy error contribution, there is still 30 meV difference between ENCUT=500 and 1200.

Thank you for your reply.
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