Is the higher the ENCUT, the higher the accuracy we get?
Posted: Fri Jan 06, 2012 5:16 am
Normally, due to ENCUT controls the size of plane wave basis sets, the answer for this question is yes.
However, in Dr. Georg Kresse's slides for the VASP course (Session 4 and Session 11), he mentioned that the pseudopotentials are always optimized for the energy cutoff 'using a minimal basis set'. And 'the PAW potentials are optimized to work at a cutoff of 250-300 eV'. So I doubt whether a result with very high cutoff energy is meaningful.
For example, I calculated some rare earth oxides, especially the ones with extended 4d and f electrons. I find the ENCUT convergence is acceptable (<20 meV for a 20-atom cell) only when the ENCUT is very large. For instance, the total energy of SrRuO3 converges at ENCUT~850 eV! 500 eV seems to converge well, but if further increase the cutoff we will get ~200 meV total energy gained. Please see the figure here.
So, in this case, whether the result with a higher cutoff has a better accuracy? or worse?
Thank you.
However, in Dr. Georg Kresse's slides for the VASP course (Session 4 and Session 11), he mentioned that the pseudopotentials are always optimized for the energy cutoff 'using a minimal basis set'. And 'the PAW potentials are optimized to work at a cutoff of 250-300 eV'. So I doubt whether a result with very high cutoff energy is meaningful.
For example, I calculated some rare earth oxides, especially the ones with extended 4d and f electrons. I find the ENCUT convergence is acceptable (<20 meV for a 20-atom cell) only when the ENCUT is very large. For instance, the total energy of SrRuO3 converges at ENCUT~850 eV! 500 eV seems to converge well, but if further increase the cutoff we will get ~200 meV total energy gained. Please see the figure here.
So, in this case, whether the result with a higher cutoff has a better accuracy? or worse?
Thank you.