Vacuum space for surface energy comparison
Posted: Wed Feb 27, 2008 10:52 pm
Dear VASP Forum:
Here is another basic question I have.
I want to calculate Fe(100) surface energies with several layers (3 to 6) to find where it converges. My question is if the vacuum spaces have to be same for each calculation. In other words, do I have to increase lattice vectors (unit cell) as layer grows in order to keep vacuum space? Please see my POSCAR examples for 3 and 4 layers. I increased z-lattice vector as layer increases.
Thank you very much
POSCAR for 3 layers:
bcc Fe(100) Surface Relaxation
2.866
1.0 0.0 0.0
0.0 1.0 0.0
0.0 0.0 3.0
3
Selective Dynamics
Cartesian
0.0 0.0 0.0 F F T
0.5 0.5 0.5 F F T
0.00.0 1.0 F F T
POSCAR for 4 layers:
bcc Fe(100) Surface Relaxation
2.866
1.0 0.0 0.0
0.0 1.0 0.0
0.0 0.0 3.5
4
Selective Dynamics
Cartesian
0.0 0.0 0.0 F F T
0.5 0.5 0.5 F F T
0.0 0.0 1.0 F F T
0.50.5 1.5 F F T
INCAR for both calculations:
SYSTEM = Fe bcc
ISTART=0
ICHARGE=2
ISMEAR = 2
SIGMA = 0.2
ENCUT = 300
ISPIN =2
NBANDS = 25
IBRION = 2
NSW = 15
POTIM = 0.2
EDIFF = 1E-5
Here is another basic question I have.
I want to calculate Fe(100) surface energies with several layers (3 to 6) to find where it converges. My question is if the vacuum spaces have to be same for each calculation. In other words, do I have to increase lattice vectors (unit cell) as layer grows in order to keep vacuum space? Please see my POSCAR examples for 3 and 4 layers. I increased z-lattice vector as layer increases.
Thank you very much
POSCAR for 3 layers:
bcc Fe(100) Surface Relaxation
2.866
1.0 0.0 0.0
0.0 1.0 0.0
0.0 0.0 3.0
3
Selective Dynamics
Cartesian
0.0 0.0 0.0 F F T
0.5 0.5 0.5 F F T
0.00.0 1.0 F F T
POSCAR for 4 layers:
bcc Fe(100) Surface Relaxation
2.866
1.0 0.0 0.0
0.0 1.0 0.0
0.0 0.0 3.5
4
Selective Dynamics
Cartesian
0.0 0.0 0.0 F F T
0.5 0.5 0.5 F F T
0.0 0.0 1.0 F F T
0.50.5 1.5 F F T
INCAR for both calculations:
SYSTEM = Fe bcc
ISTART=0
ICHARGE=2
ISMEAR = 2
SIGMA = 0.2
ENCUT = 300
ISPIN =2
NBANDS = 25
IBRION = 2
NSW = 15
POTIM = 0.2
EDIFF = 1E-5