DOS and the effect of NBANDS
Posted: Wed May 21, 2008 4:05 am
Dear VASP forum,
I am trying to calculate the full DOS for the d-orbitals of different transition metals near the fermi level such as a surface slab of Cr(110). In this case, I would like to calculate the full 3d orbital d-band from below the fermi level to the unoccupied portion above the fermi level. I've noticed that I need to increase NBANDS from the default program value in order to get the full d-band which makes sense but my question is what happens if NBANDS is too large? Is it possible that if I include too many BANDS that instead of just having 3d orbitals that I could also include 4d or other higher unoccupied orbitals in my calculation of the angularly resolved DOS? I ask because I notice that my number of states per atom will pass 10 d-states/atom if I increase NBANDS to higher numbers. If this is the case, is there a way to distinguish which d-orbital states are from which primary quantum number so that I can just single out the 3d states in my DOSCAR file?
Thank you very much!
q365
I am trying to calculate the full DOS for the d-orbitals of different transition metals near the fermi level such as a surface slab of Cr(110). In this case, I would like to calculate the full 3d orbital d-band from below the fermi level to the unoccupied portion above the fermi level. I've noticed that I need to increase NBANDS from the default program value in order to get the full d-band which makes sense but my question is what happens if NBANDS is too large? Is it possible that if I include too many BANDS that instead of just having 3d orbitals that I could also include 4d or other higher unoccupied orbitals in my calculation of the angularly resolved DOS? I ask because I notice that my number of states per atom will pass 10 d-states/atom if I increase NBANDS to higher numbers. If this is the case, is there a way to distinguish which d-orbital states are from which primary quantum number so that I can just single out the 3d states in my DOSCAR file?
Thank you very much!
q365