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IDIPOL=3

Posted: Thu Apr 16, 2009 8:32 am
by jelenajelic
Dear VASP users,
I have a question. I am trying to optimize structure of PdO(101) surface oxide over Pd(100) and I am using mirror sufraces. My INCAR file looks like:
ENCUT = 400.000
PREC = NORMAL
ISPIN = 1 non-spin polarized calculation
NELM = 400; NELMDL= 0 # of ELM steps
EDIFF = 0.1E-03 stopping-criterion for ELM

Ionic Relaxation
EDIFFG = 0.1E-02 stopping-criterion for IOM
NSW = 200 number of steps for IOM
IBRION = 2 ionic relax: 0-MD 1-quasi-New 2-CG
POTIM = 0.5 time-step for ion-motion
ISIF = 2
GGA = 91
VOSKOWN = 1
ISYM = 0
ISMEAR = 1
SIGMA= 0.2
IDIPOL = 3

Electronic Relaxation 2
IALGO = 48 algorithm
LWAVE = F
LCHARG = F
LREAL = T real-space projection

NSIM = 4
NPAR = 4
LPLANE = T
LSCALU = F

My OSZICAR looks normal but when I do "grep F OSZICAR" I get somethin like this:

1 F= -.19545900E+03 E0= -.19541967E+03 d E =-.195459E+03
2 F= 0.24854544E+03 E0= 0.24858582E+03 d E =0.444004E+03
3 F= 0.17670886E+04 E0= 0.17671299E+04 d E =0.196255E+04
4 F= -.19602948E+03 E0= -.19598845E+03 d E =-.570473E+00
5 F= 0.25466676E+05 E0= 0.25466717E+05 d E =0.256627E+05
6 F= -.19093105E+03 E0= -.19089005E+03 d E =0.509842E+01
7 F= -.19645095E+03 E0= -.19641140E+03 d E =-.551990E+01
8 F= -.19662824E+03 E0= -.19659177E+03 d E =-.569719E+01
9 F= -.19681893E+03 E0= -.19678364E+03 d E =-.190687E+00
10 F= 0.55606747E+04 E0= 0.55607088E+04 d E =0.575730E+04
11 F= -.10101328E+03 E0= -.10098006E+03 d E =-.566169E+04
12 F= -.19712514E+03 E0= -.19709303E+03 d E =-.575780E+04
13 F= -.19721669E+03 E0= -.19718543E+03 d E =-.915564E-01
14 F= -.19723144E+03 E0= -.19720030E+03 d E =-.106307E+00
15 F= 0.31119246E+05 E0= 0.31119277E+05 d E =0.313165E+05
16 F= 0.10571500E+04 E0= 0.10571822E+04 d E =0.125438E+04
17 F= -.19737721E+03 E0= -.19734491E+03 d E =-.125453E+04
18 F= 0.69389986E+04 E0= 0.69390311E+04 d E =0.588185E+04
19 F= -.16343625E+03 E0= -.16340352E+03 d E =-.710243E+04
20 F= -.19751361E+03 E0= -.19748091E+03 d E =-.713651E+04
21 F= 0.91657610E+02 E0= 0.91691293E+02 d E =-.684734E+04
22 F= 0.16949904E+05 E0= 0.16949937E+05 d E =0.100109E+05
23 F= 0.29534168E+05 E0= 0.29534200E+05 d E =0.125843E+05
24 F= -.19760852E+03 E0= -.19757626E+03 d E =-.171475E+05
25 F= -.19763972E+03 E0= -.19760739E+03 d E =-.311941E-01
26 F= -.19764708E+03 E0= -.19761473E+03 d E =-.385586E-01
27 F= -.19269384E+03 E0= -.19266145E+03 d E =0.491468E+01
28 F= -.19011264E+03 E0= -.19008011E+03 d E =0.749589E+01
29 F= 0.59360011E+03 E0= 0.59363253E+03 d E =0.791209E+03
30 F= -.19757369E+03 E0= -.19754107E+03 d E =-.791174E+03
31 F= 0.11732273E+03 E0= 0.11735561E+03 d E =-.476277E+03
32 F= -.19767342E+03 E0= -.19764049E+03 d E =-.314996E+03
33 F= -.19769917E+03 E0= -.19766620E+03 d E =-.315022E+03
So, my question is: is there a mistake in my INCAR file? Second, if I use mirror surfaces do I need to use IDIPOL=3 or if I use IDIPOL=3 do I need mirror surfaces?!

Thank's. I will greatly appreciate any answer!

Re: IDIPOL=3

Posted: Wed Sep 11, 2024 1:58 pm
by support_vasp

Hi,

We're sorry that we didn’t answer your question. This does not live up to the quality of support that we aim to provide. The team has since expanded. If we can still help with your problem, please ask again in a new post, linking to this one, and we will answer as quickly as possible.

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